Write an equation in slope intercept form of a line that passes through the point (2,4) and is perpendicular to the graph of x-6y=2

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asked Jun 7, 2015 156k views

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Adamek · Answer 1 · 2015-06-13T19:27:45+0000

-6y=2-x
y=x/6-1/3
so the slope for this line is 1/6,
therefore the slope for line perpendicular to this line is -6
y=mx+b
subsitute (2,4)in
4=-6*2+b
you get b=16
so the equation is y=-6x+16

Write an equation in slope intercept form of a line that passes through the point (2,4) and is perpendicular to the graph of x-6y=2

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