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He graph below shows the velocity f(t) of a runner during a certain time interval:

graph of line going through ordered pairs 0, 4 and 4, 8. Graph of another line going through ordered pairs 4, 8 and 8, 0. Label on the x axis is time in second and label on the y axis is velocity in meter per second

Which of the following describes the intercepts on the graph?

The initial velocity of the runner was 4 m/s, and the runner stopped after 8 seconds.
The initial velocity of the runner was 8 m/s, and the runner stopped after 4 seconds.
The initial acceleration of the runner was 4 m/s2,

He graph below shows the velocity f(t) of a runner during a certain time interval-example-1
User Carbo
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2 Answers

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Answer is "the initial velocity of the runner was 4 m/s, and the runner stopped after 8 seconds".

This is a velocity - time graph.

At t = 0 s, the graph has a velocity as 4 m/s. This means, the runner has an initial velocity as 4 m/s.

At t = 4 s, the runner has reached his maximum velocity as 8 m/s and acceleration is 1 m/s².

After t = 4 s, the velocity has decreased with the time means it is a negative acceleration.

At t = 8 s, the velocity of the runner has reached to zero means runner has stopped after 8 seconds.

User Leonid Makarov
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4 votes
The following that describes the intercepts on the graph is "The initial velocity of the runner was 4 m/s, and the runner stopped after 8 seconds." It is because the starting point of the line is at 4 and then the ending point is at 8.

User Karim Tawfik
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