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Answer:
Michael's cube has 4 times the surface area of Ayasha's cube
Explanation:
When linear dimensions of similar figures are scaled by a factor k, their surface areas are scaled by the factor k², and their volumes are scaled by the factor k³.
Here, Michael's cube is 2 times the length of Ayasha's cube, so the surface area of his cube will be 2² = 4 times the surface area of Ayasha's cube.
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The surface area of the cube is ...
A = 6s²
so Ayasha's cube has an area of ...
A = 6(7 m)² = 294 m²
Michael's cube has an area of ...
A = 6(2·7 m)² = 4·294 m² = 1176 m²