Question

A school club purchased a total of 50 cheese pizzas and supreme pizzas. Cheese pizzas cost$10 each, and supreme pizzas cost $12 each.Which system of equations can be used to find the number of cheese pizzas, x, and thenumber of supreme pizzas, y, if the total cost of the pizza was $536?A X= 50-y12x + 10y = 536WillBX = 536 - y12x + 10y = SOсx = 50-10x + 12y = 536Dx 536 - y10x + 12y = 50

Answer 1

Concept

Write two equations, one for the total number of Pizzas and the other for the total cost.

Next,

Let a number of cheese pizzas x, and the number of supreme pizzas y.

Total Pizzas = 50

x + y = 50 .................................. (1)

Cheese pizzas cost $10 each, and supreme pizzas cost $12 each.

10x + 12y = 536 ......................................... (2)

Next, from equation 1, make x subject of the formula.

Therefore, y = 50 - x

Hence,

y = 50 - x

10x + 12y = 536

Final answer

Option C

y = 50 - x

10x + 12y = 536