Question

Convert 1.14 moles to grams .This is the mass of acetic acid in a 15.00ml sample

Answer 1

68.4 g of CH3COOH.

Step-by-step explanation:

Acetic acid has the formula CH3COOH. To convert from moles to grams or vice versa, we have to know the molar mass of the given compound.

If we go to see the periodic table, you can see that the molar mass of carbon (C) is 12 g/mol, of hydrogen (H) is 1 g/mol, and oxygen (O) is 16 g/mol.

To calculate the molar mass we have to do an algebraic sum with the number of atoms that we have in the formula.

In this case, you can note that from CH3COOH, we have 2 carbons, 4 hydrogens, and 2 oxygens. The calculation will look like this:

`\begin{gathered} Molar\text{ mass CH}_3COOH=2\cdot12(g)/(mol)+4\cdot1(g)/(mol)+2\cdot16(g)/(mol), \\ \\ Molar\text{ mass CH}_3COOH=24(g)/(mol)+4(g)/(mol)+32(g)/(mol), \\ \\ Molar\text{ mass CH}_3COOH=60(g)/(mol). \end{gathered}`

The molar mass of CH3COOH is 60 g/mol. This is telling us that we have 60 g of CH3COOH in 1 mol of CH3COOH.

Now let's convert 1.14 moles of CH3COOH to grams using its molar mass, as follows:

`1.14\text{ moles CH}_3COOH\cdot\frac{60\text{ g CH}_3COOH}{1\text{ mol CH}_3COOH}=68.4\text{ g CH}_3COOH.`

The answer would be 68.4 g of CH3COOH.