Question

PLEASE HELP ASAP

The line that is the perpendicular bisector of the segment whose endpoints are R(-1, 6) and S(5, 5)

Indicate the equation of the given line in standard form.

Answer 1

6x-y=13/2

Explanation:

Answer 2

First find midpoint:
`\left( (-1+5)/(2), (6+5)/(2)\right) = (2, 5.5)`

Find slope of line that passes through R and S: slope =
`(6-5)/(-1-5) = (-1)/(6)`

Negative reciprocal of slope to get slope of perpendicular: new slope = 6

Line will be:
`y-5.5=6(x-2)`


`y = 6x - 6.5`