Question

The metal block had a mass of 1.50kg

Answer 1

The amount of heat energy lost by the metal is

E = 200 J/kg*C x 1.5kg x (100–20) = 24000 J

That is transferred to the liquid, raising it's temperature

24000 J = 1,000 kg/J*C x 3kg x ∆T

∆T = 8

Since the liquid started at 0ºC, the final temp is 8ºC