Question

Evaluate 3X^2-14X-49/X-7
the quotient of the equation is __X+__

Answer 1

I hope this helps you

Answer 2

`3x+7`

Explanation:

`(3x^2-14x-49)/(x-7)`

before dividing this fraction , lets factor the numerator

`3x^2-14x-49`

Product is -49 and sum is -14, lets break the middle term using factors

`(3x^2+7x)+ (-21x-49)`

Take out GCF from each group

`x(3x+7)-7(3x+7)`

`(3x+7)(x-7)`

Now we replace the factors in the numerator

`((3x+7)(x-7))/(x-7)`

We have (x-7) at the top and bottom , so we cancel it out

`3x+7`