Question

Consider the trinomial 9x2 + 21x + 10. What value is placed on top of the X? What value is placed on the bottom of the X? What is the factored form of 9x2 + 21x + 10?

Answer 1

1: 90
2: 21
3: (3x+2)(3x+5)

Answer 2

Answer: 1) Value is placed on top of the X =90

2) Value is placed on the bottom of the X =21

3) Factored form will be (3x+5)(3x+2)

Explanation:

Since we have given that

`9x^2 + 21x + 10`

As we know the quadratic form :

`ax^2+bx+c=0`

1) Value is placed on top of the X is given by

`a* c=9* 10=90`

2) Value is placed on the bottom of the X is given by

`b=21`

3) Factorised form:

We will use "Split the middle term":

`9x^2 + 21x + 10\\\\=9x^2+15x+6x+10\\\\=3x(3x+5)+2(3x+5)\\\\=(3x+2)(3x+5)`

Hence, Factored form will be

(3x+5)(3x+2)