Question

24x^2 - 45x - 21 = 0

Answer 1

`24x^2-45x-21=0 3(8x^2-15x-7)=0 /:3 8x^2-15x-7=0 a=8... b=-15.... c=-7 delta= b^2-4ac=449 x_1= (15- √(449) )/(16) x_2= (15+ √(449) )/(16)`√ΔΔΔΔΔΔΔΔΔ

Answer 2

`24x^2-45x-21=0\\ 3(8x^2-15x-7)=0\\ 8x^2-15x-7=0\\ \Delta=(-15)^2-4\cdot8\cdot(-7)=225+224=449\\ √(\Delta)=√(449)\\ x_1=(-(-15)-√(449))/(2\cdot8)=(15-√(449))/(16)\\ x_2=(-(-15)+√(449))/(2\cdot8)=(15+√(449))/(16)`