How much energy is stored in a room 3.0 m by 4.0 m by 2.4 m due to the earth's magnetic field with a strength of 5.0 × 10-5 T? (μ0 = 4π × 10-7 T · m/A)

Question

asked Feb 17, 2017 157k views

1 Answer

Michaeltwofish · Answer 1 · 2017-02-22T12:01:19+0000

Answer:

The energy stored in a room is 0.0286 Joules.

Step-by-step explanation:

Given that,

The dimensions of the room are 3 m by 4 m by 2.4 m

The strength of the Earth's magnetic field,
$B=5* 10^(-5)\ T$

We need to find the energy stored in a room due to the Earth'a magnetic field. It is given by :

$E=(B^2)/(2\mu_o)V$

Here,

V is the volume of the room

$E=((5*10^(-5))^(2))/(2*4\pi*10^(-7))*(3*4*2.4)\\\\E=0.0286\ J$

$E=0.0286\ J$

So, the energy stored in a room is 0.0286 Joules. Hence, this is the required solution.