106k views
3 votes
Find the values of x and y that maximize the objective function P=3x+2y for the graph. What is the maximum value? Show all work.

Find the values of x and y that maximize the objective function P=3x+2y for the graph-example-1
User Ian Abbott
by
7.7k points

2 Answers

2 votes

Answer:

27

Explanation:

Since coeficient in front of x is larger than coeficient in front of y that means that value of function P depends more on x than on y. That means that we should look for highest posible x and see highest posible y for that x.

Highest x value is 9 and we can only pick y=0 for it

P = 27

Note that if u decrease x by 1 we can take y=1 but now our value is:

P = 8*3 + 2*1 = 26 which is just confirmation why P depends more on x than on y due to coefficient in front of x.

And or

Answer:

27

Explanation:

To find the maximum, input the vertices (0,8), (5,4) and (9,0) into the objective function (P = 3x + 2y) to determine which vertex obtains the maximum value.

NOTE: I don't understand why (5,4) was given on your graph as a vertex.

(0,8): P = 3(0) + 2(8) = 0 + 16 = 16

(5,4): P = 3(5) + 2(4) = 15 + 8 = 23

(9,0): P = 3(9) + 2(0) = 27 + 0 = 27 THIS IS THE LARGEST (MAX) P-VALUE

User Richard Morgan
by
8.2k points
2 votes
Since coeficient in front of x is larger than coeficient in front of y that means that value of function P depends more on x than on y. That means that we should look for highest posible x and see highest posible y for that x.

Highest x value is 9 and we can only pick y=0 for it

P = 27

Note that if u decrease x by 1 we can take y=1 but now our value is:
P = 8*3 + 2*1 = 26 which is just confirmation why P depends more on x than on y due to coefficient in front of x.
User Snaxib
by
8.1k points