Question

This coordinate plane shows the shape of a hang glider. The perimeter of the glider is to be trimmed with a special material. What is the minimum length of material needed?

Answer 1

X = 24 ft Of Materials

Y = 2 ft Of Distance

X = (12,7)

Y = (0,2)

Using The Pythagoras Theorem

`D=\sqrt{12^(2)+5^(2)}=13`

Total lenght is:

`\left[\begin{array}{ccc}3*13+24+4=26\\26+28=54\end{array}\right]`

Answer 2

On x axis we will need 24 feets of material. on y axis we will need 2 times 2 feet which is 4 feet for those sides.

now there are lines that are not paralel to x and y so it is not that simple (but not hard either) to calculate lenghts. we can use formula for distance between 2 dots.

we will use dots: (12,7) and (0,2)
from that using pythagoras theorem we can see that distance is:
d = √12^2 + 5^2 = 13
Total lenght is:

2*13 + 24 + 4 = 26 + 28 = 54