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24 votes
24 votes
I need help to find the nearest tenth of this triangle. I've been struggling for about 30 minutes now. I will include the photo!

I need help to find the nearest tenth of this triangle. I've been struggling for about-example-1
User Michael David Watson
by
2.6k points

1 Answer

21 votes
21 votes

Area of the triangle PQR can be determined as,


\begin{gathered} \Delta=(1)/(2)* QP* RS \\ =(1)/(2)*8\text{ cm}* RP\sin 39^(\circ) \\ =(1)/(2)*8\text{ cm}*15\operatorname{cm}*\sin 39^(\circ) \\ =37.759cm^2 \end{gathered}

Thus, the required area of the triangle to the nearest tenth is 37.8 square centimeters.

I need help to find the nearest tenth of this triangle. I've been struggling for about-example-1
User Max Stewart
by
3.0k points