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(2x−12)+( 1 2 xy−10) (2x-12)+(12xy-10) for x=8 x=8 and y=2

(2x−12)+( 1 2 xy−10) (2x-12)+(12xy-10) for x=8 x=8 and y=2
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(2x−12)+( 1 2 xy−10) (2x-12)+(12xy-10) for x=8 x=8 and y=2

User Zaklina
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1 Answer

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(2(8)-12)+(12(8)(2)-10)
(16-12)+(132-10)
4+122=126
THE ANSWER WOULD BE 126 :D

User Nick Anderegg
by
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