Question

What is the value of i^97 - i

Answer 1

this can also be explained as b on edg

Answer 2

`if\ i\ is\ the\ imaginary\ unit\ (i=√(-1)\Rightarrow i^2=-1):\\\\i^(97)-i=i(i^(96)-1)=i(i^(48\cdot2)-1)=i[(i^2)^(48)-1]=i[(-1)^(48)-1]\\\\=i(1-1)=i\cdot0=0\\\\therefore\ \boxed{i^(97)-i=0}`