Question

if a trend line had the equation
`y = - 3.7x + 0.68`what y-value would you expect to obtain when x has the following values? a. 13; b. 0; c. 5.8; d. 7.7

Answer 1

Step 1: Write out the equation given in the question

`y=-3.7x+0.68`

Step 2: Solve for y by substituting each of the values of x given in the question

`\begin{gathered} (a)\text{when x=13} \\ y=-3.7(13)+0.68 \\ y=-48.1+0.68 \\ y=-47.42 \end{gathered}`
`\begin{gathered} (b)\text{when x=0} \\ y=-3.7(0)+0.68 \\ y=0+6.8 \\ y=0.68 \end{gathered}`
`\begin{gathered} (c)\text{when x=5.8} \\ y=-3.7(5.8)+0.68 \\ y=-21.46+0.68 \\ y=-20.78 \end{gathered}`
`\begin{gathered} (d)\text{ when x=7.7} \\ y=-3.7(7.7)+0.68 \\ y=-28.49+0.68 \\ y=-27.81 \end{gathered}`

Hence, when x= 13, y= -47.42; x=0, y= 0.68; x=5.8, y=-20.78; x=7.7, y=-27.81