57.5k views
2 votes
A soccer player kicks a soccer ball at +10.0 m/s at an angle of 60°. What are the horizontal and vertical components of velocity of the kick?

User Paul Weber
by
7.3k points

2 Answers

5 votes
This seems like a calculus problem. I'm assuming you would use cos and sin. so here's the vertical component +10.0m/s multiplied by sin60 = 8.66 rounded to the hundreths place. Now for horizontal, that would be +10.0m/s multiplied by cos60 = 5. hope this helped.
User Mike Gardiner
by
8.6k points
6 votes

Answer:

Horizontal component:
V_(x)=+5m/s

Vertical component:
V_(y)=+8.66m/s

Step-by-step explanation:

We have the launch speed
V =+ 10m/s and the angle of 60°, so the components of the speed
V_(x) and
V_(y) are those shown in the attached image.


V_(x) which is the horizontal component of the velocity can be found by multiplying the cosine of the angle by the initial velocity:


V_(x)=+10m/s(cos60)\\V_(x)=+10m/s(0.5)\\V_(x)=+5m/s


V_(y) which is the verticalcomponent of the velocity is found by multiplying the sine of angle by the initial velocity


V_(y)=+10m/s(sin60)\\V_(y)=+10m/s(0.866)\\V_(y)=+8.66m/s

In summary:

Horizontal component:
V_(x)=+5m/s

Vertical component:
V_(y)=+8.66m/s

A soccer player kicks a soccer ball at +10.0 m/s at an angle of 60°. What are the-example-1
User Chris Baswell
by
8.5k points