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Jack and Walter work in a store's gift-wrapping department. Jack can wrap 28 boxes in 2 hours, while Walter takes 3 hours to wrap 36 boxes of the same size. One day they work together for t hours to gift wrap 65 boxes. Which equation models this situation?

User Bidisha
by
8.3k points

2 Answers

4 votes
"Jack can wrap 28 boxes in 2 hours"
Jack wraps 28 boxes/(2 hours) = 14 boxes/hour

"Walter takes 3 hours to wrap 36 boxes"
Walter wraps 36 boxes/(3 hours) = 12 boxes/hour

Together they wrap 14+12 = 26 boxes per hour.
t hours × 26 boxes/hour = 65 boxes
User Jason Rosendale
by
8.3k points
0 votes

Answer: They work for 2.5 hours to gift wrap 65 boxes.

Explanation:

Since we have given that

Number of boxes Jack can wrap = 28

Time taken by him = 2 hours

Number of boxes Walter can wrap = 36

Time taken by him = 3 hours

Work done by Jack in 1 hour is given by


(2)/(28)\\\\=(1)/(14)

Work done by Walter in 1 hour is given by


(3)/(36)\\\\=(1)/(12)

So, Work done by both Jack and Walter in 1 hour is given by

L.C.M. of
((1)/(14),(1)/(12)) is
=(l.c.m.\ of \ numerator)/(h.c.f\ of\ denominator)=(1)/(2)

Number of units done by Jack is given by


((1)/(2))/((1)/(14))\\\\=(14)/(2)\\\\=7\ units

Number of units done by Walter is given by


((1)/(2))/((1)/(12))\\\\=(12)/(2)\\\\=6\ units

So, Let the number of hours be 't' .


7t+6t=(1)/(2)* 65\\\\13t=(1)/(2)* 65\\\\t=(1)/(2)* (65)/(13)\\\\t=(5)/(2)\\\\t=2.5\ hours

So, They work for 2.5 hours to gift wrap 65 boxes.

User Hck
by
8.2k points
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