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Solving Systems of Equations by Substitution

y=1/2x+5

y=-3/2x-7

User Skeeter
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1 Answer

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\left\{\begin{array}{ccc}y=(1)/(2)x+5\\y=-(3)/(2)x-7\end{array}\right\\\\subtitute:\\\\(1)/(2)x+5=-(3)/(2)x-7\ \ \ \ |subtract\ 5\ from\ both\ sides\\\\(1)/(2)x=-(3)/(2)x-12\ \ \ \ |add\ (3)/(2)x\ to\ both\ sides\\\\(4)/(2)x=-12\\\\2x=-12\ \ \ \ |divide\ both\ sides\ by\ 2\\\boxed{x=-6}\\\\subtitute\ value\ of\
User Punjabi
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