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NO LINKS!! What is the area of this figure? Part 17​

NO LINKS!! What is the area of this figure? Part 17​-example-1

2 Answers

9 votes

Solution:

Draw the whole rectangle.

Refer to image~

Subtract the area of the unshaded region from the rectangle's area.

  • {41 x 20} - {(5 x 6) + (10 x 13)} = Area of figure
  • => 820 - {30 + 130} = Area of figure
  • => 820 - 160 = Area of figure
  • => 660 in² = Area of figure
NO LINKS!! What is the area of this figure? Part 17​-example-1
User Thuan Nguyen
by
4.7k points
7 votes

Answer:

660 in²

Explanation:

The area of this figure looks like it is best computed by subtracting the areas of the empty corners from the area of the "bounding box."

The overall dimensions of the figure are ...

horizontal: 31 in + 10 in = 41 in

vertical: 13 in + 7 in = 20 in

Then the area of the bounding box is ...

A = LW = (41 in)(20 in) = 820 in²

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The area of the upper left empty space is ...

A = (6 in)(5 in) = 30 in²

The area of the lower right empty space is ...

A = (10 in)(13 in) = 130 in²

Then the area of the figure is ...

total shaded area = (820 -30 -130) in² = 660 in²

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Additional comment

The formula for the area of a rectangle is ...

A = LW . . . . . . where L is the length, and W is the width

User Joe Audette
by
4.9k points