Question

Find the area of this triangle.Round to the nearest tenth.8 mho62°12 m[?] m2

Answer 1

we have two sides and a known angle, then we use the following formula for area

`=(a\cdot b\cdot\sin C)/(2)`

where a = 8. b = 12 and C = 62°, so

`\begin{gathered} A=(8\cdot12\cdot\sin 62)/(2) \\ A=(96\cdot\sin 62)/(2) \\ A=48\cdot\sin 62 \\ A=42.4 \end{gathered}`

answer: 42.4 m^2