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How do i write 12+(43-7)÷6 in order of operations

How do i write 12+(43-7)÷6 in order of operations
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2 votes
How do i write 12+(43-7)÷6 in order of operations

User AdamNYC
by
7.6k points

2 Answers

3 votes
using PEMDAS

P: parenthesis
E: exponents
M: multiplication
D: division
A: addition
S: subtraction

In this case 12+(43-7)÷6
you need to do parenthesis first (43-7)
then division, ÷6
then addition, 12+

12+(43-7) ÷ 6
= 12 + 36 ÷ 6
= 12 + 6
= 18
User Soteria
by
7.9k points
6 votes
Bidmas so 43-7 then divide by 6 then add 12
User Forlayo
by
8.5k points
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