Question

A circuit with a battery, a 6 Ω resistor, a 15 Ω resistor, and a 27 Ω resistor in parallel. The total voltage is the system is 10.0 V. What is the current through the battery?

Answer 1

Resistors in parallel:

R1=6 Ω

R2=15 Ω

R3=27 Ω

Total voltage = V = 10 V

To find the total R:

`(1)/(RT)=(1)/(R1)+(1)/(R2)+(1)/(R3)`
`(1)/(RT)=(1)/(6)+(1)/(15)+(1)/(27)`
`(1)/(RT)=(73)/(270)`
`270\cdot1=RT\cdot73`
`(270)/(73)=RT`

`RT=3.7`

RT=3.7Ω

Ohm's Law

V=I x R

I = V/R = 10 V / 3.7 Ω = 2.7 A