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What positive number (x) satisfies the equation 3x^2=27^3?
Please help!!

User Cousin
by
3.6k points

2 Answers

10 votes

Answer:

x = 2187

Explanation:

3x^2 = 9x

27^3 = 19,683 9x = 19,683

19683 ÷ 9 = 2187

User Denys Kotsur
by
3.2k points
10 votes

The positive value of x that satisfies the equation is 27.

To solve equations involving indices, we make sure that the bases are equal. Indices is always in the form axⁿ. Where n is the index , a is the coefficient and x is the base.

Solving

3x² = 27³

3x² = (3³)³

x² = (3³)³/3

x² = 3⁶

x = √3⁶

x = 3³

x = 27

Therefore the positive value of x that satisfies the equation is 27

User Niboshi
by
3.8k points