Okay! This took forever. BUT I got the answers!!!
You can use substitution and plug in the y value given as x+3 into xy=10.
x(x+3)=10
or
x^2+3x=10
or
x^2+3x-10=0
Then you divide the -10 into two different factors, I did 2 and -5.
x^2 is equal to xx, so now you have one x for each factor of the -10:
(x+2)(x-5)=0
This means x is either 2 or -5, and when you plug in these values to the equation y=x+3, you get:
(2,5)
and
(-5,-2)
Which are your two intersecting points!