Question

(k^3-8k^2+16k-5)÷(k-5)

Answer 1

(Kx3-16k^ + 16k-5):(k-5)
(3k-16k^+16k-5):(k-5)
(19k-16k^-5):(k-5)
19-16k^-5
K-5

When is this little signed ^ go a n and this : signifícate a división signed and in down of 19-16k^-5 go a Scratch and k-5

Answer 2

Start by factoring the numerator. We know that
`(k-5)` is a factor. So, your answer becomes:


`(k -5)(k^2-3k+1) / (k-5)`

Now we have two of the same terms
`(k-5)` in the numerator and the denominator, we cancel them out and are left with:


`k^2-3k+1`