Question

Find the inverse of the given function h(x)=log(x)

Answer 1

to solve
replace h(x) with y
switch x and y
solve for y
replace y with h⁻¹(x)

remember that
logx is base 10
and that

`log_xy=b` means
`x^b=y`
so


y=log(x)
x=log(y)
convert, assume base 10

`10^x=y`
ha! that's already solved for y

`y=10^x`

`h^(-1)(x)=10^x`

Answer 2

Assuming that's log base 10, the inverse would be k(x) = 10^x

h(k(x)) = x
and
k(h(x)) = x