Question

How do I solve this problem 16x^2 + 1 =8x Using this quadractic x=-b+ square root b-4ac /2a

show work so I can better see

Answer 1

minus 8x both sides
16x^2-8x+1=0
for
ax^2+bx+c=0
x=
`(-b+/- √(b^2-4ac) )/(2a)`
a=16
b=-8
c=1
x=
`(-(-8)+/- √((-8)^2-4(16)(1)) )/(2(16))`
x=
`(8+/- √(64-64) )/(32)`
x=
`(8+/- √(0) )/(32)`
x=
`(8+/-0 )/(32)`
x=
`(8)/(32)`
x=
`(4)/(16)`
x=
`(2)/(8)`
x=
`(1)/(4)`

Answer 2

16x² + 1 = 8x First, make this a quadratic equation. Subtract 8x from both sides
16x² -8x + 1 = 0 Now, since ax² + bx + c = 0 is quadratic equation form, a = 16, b = -8, and c = 1. Plug those into the quadratic formula.
x =
`(-b \pm √(b^2 - 4ac) )/(2a)` Plug in your numbers
x =
`(-(-8) \pm √((-8)^2 - 4(16)(1)) )/(2(16))` Simplify the double negative (- (-8))
x =
`(8 \pm √((-8)^2 - 4(16)(1)) )/(2(16))` Simplify (-8)²
x =
`(8 \pm √(64 - 4(16)(1)) )/(2(16))` Simplify 4(16)(1)
x =
`(8 \pm √(64 - 64) )/(2(16))` Subtract 64 from 64
x =
`(8 \pm √(0) )/(2(16))` Mutiply 2 and 16
x =
`(8 \pm √(0) )/(32)` Get rid of the
`√(0)`
x =
`(8)/(32)` Simplify
x =
`(1)/(4)`