What is the vertex of the parabola defined by the equation(x − 2)^2 = -12(y − 2)?

asked Apr 9, 2017 143k views

5 votes

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3 votes

x^2-4x+4=-12y+24
(x^2-4x-20)/-12=y
quadratic => vertex is (-b/2a,f (-b/2a))
Note it is a minimum since coefficient a is positive

Hong Wei Wang answered Apr 12, 2017

7.9k points

4 votes

I got (2,2) as the answer

N D answered Apr 15, 2017

by N D

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