4.3k views
3 votes
Find a polynomial function f(n) such that f(1), f(2), ... , f(8) is the following sequence.2, 8, 14, 20, 26, 32, 38, 44

User Ichthyo
by
8.3k points

1 Answer

1 vote
We can recognize the sequence is an arithmetic progression by noticing that the common difference between each term is 6.

f(n) = a+(n-1)d
where f(n) is the sequence
n is the term number
d is the common difference
and a is the starting term

We are well aware that our starting term, and hence a, is 2 and our difference, and hence d, is 6.
So our polynomial function is

f(n) = 2+6(n-1)

User Xingbin
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories