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Find the zeros of g(x)=x2+5x−24g

2 Answers

3 votes
❀Hm, I'm pretty sure you should solve for g. If so, then the first step we would need to do is add 24g to both sides:
gx+24g=x^224g+5x+24g
gx+24g=x^2+5x
❀Now you are going to factor out variable g:
g(x+24)=x^2+5x
❀Finally divide both sides by x+24:

(g(x+24))/(x+24 ) = (x^2+5x )/(x+24 )

❀Your answer is:

g= (x^2+5x )/(x+24 )

❀Good Luck❀
User Peralmq
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6 votes
I'll assume the 'g' at the end is a typo and shouldn't be there. Set the right side equal to zero and solve for x

x^2+5x-24 = 0

(x+8)(x-3) = 0

x+8 = 0 or x-3 = 0

x = -8 or x = 3

The zeros or roots are x = -8 or x = 3
User Cool Hand Luke
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7.0k points