Question

How many moles of potassium bromide is needed to produced 51.62 moles of bromine?

Answer 1

Option A = 103.2 mol KBr

Step-by-step explanation

Given:

`Cl_2+2KBr\rightarrow2KCl+Br_2`

Moles of bromine = 51.62 moles

Required: Moles of KBr

Solution

Use the stoichiometry to calculate the the moles of KBr

The molar ration between Br and KBr is 1:2

Therefore the moles of KBr = 51.62 mol x 2 = 103.24 mol