Question

The parachute on a drag racing car deploys at the end of a run. If the car has a mass of 820 kg and the car is moving 36 m/s, what magnitude force (in N) is necessary to stop the car in a distance of 980 m?

Answer 1

In order to determine the required force to stop the car, proceed as follow:

Calculate the deceleration of the car, by using the following formula:

`v^2=v^2_o-2ax`

where,

v: final speed = 0m/s (the car stops)

vo: initial speed = 36m/s

x: distance traveled = 980m

a: deceleration of the car= ?

Solve the equation above for a, replace the values of the other parameters and simplify:

`\begin{gathered} a=(v^2_o-v^2)/(2x) \\ a=((36(m)/(s))^2-(0(m)/(s))^2)/(2(980m))=0.66(m)/(s^2) \end{gathered}`

Next, consider that the formula for the force is:

`F=ma`

where,

m: mass of the car = 820 kg

a: deceleration of the car = 0.66m/s^2

Replace the previous values and simplify:

`F=(820kg)(0.66(m)/(s^2))=542.20N`

Hence, the required force to stop the car is 542.20N