13.6k views
5 votes
What is the vertex and the equation of the axis of symmetry of the graph of y=x2-6x-7?

User Philayyy
by
7.9k points

2 Answers

5 votes
x= -b over 2a = --6 over 2×1=3
y=3²-6(3)-7=-16
vertex is (3,-16)
axis of symmetry is 3
User Sergei Zinovyev
by
9.3k points
1 vote

Answer:

The vertex is (3,-16) and axis of symmetry is 3

Explanation:

The vertex of a quadratic equation
f(x)=ax^(2)+bx+c is calculated as
((-b)/(2a),f((-b)/(2a)))

and the axis of symmetry is
(-b)/(2a)

Compare equation
y=x^(2)-6x-7 with
f(x)=ax^(2)+bx+c

Where a= 1 and b = -6

so,
x=(-b)/(2a)=(-(-6))/(2)


x=3

Now, put the value of x=3 in
y=x^(2)-6x-7


y=(3)^(2)-6(3)-7


y=9-18-7


y=-16

Therefore, the vertex is (3,-16) and axis of symmetry is 3

User Janadari Ekanayaka
by
8.9k points

No related questions found