Question

11.CA-V-12X+110. A catapult for a science class launches an object into the air creating the arc of aparabola. The arc can be modeled by the equation y=-16° + 24. How many seconds is theobject in the air12

Answer 1

Answer : t = 0.75 second

Given that

`\begin{gathered} y=-16t^2\text{ + 24t} \\ To\text{ calculate the number of time in seconds, we n}eed\text{ to differentiate y with t} \\ \text{ dy/dt = -2 }\cdot16t^(2-1)+1\cdot24t^(1-1) \\ \text{ dy/dt = -32t + 24} \\ \text{ let dy/dt = 0} \\ 0\text{ = -32t + 24} \\ 32t\text{ = 24} \\ \text{Divide both sides by 32} \\ t\text{ = }(24)/(32) \\ t\text{ = 0.75 second} \end{gathered}`