Question

13 units find area of sector GHJ. In circle H with m/GHJ 36 and GH Round to the nearest hundredth. H G

Answer 1

`\text{Area}_(cir\sec )=53.09\text{ square units}`

Step-by-step explanation

The area of a circular sector is given by:

`\text{Area}_(cir\sec )=\pi r^2\cdot((\Theta)/(360))`

where r is the radius and theta is the angle

then

Let

angle=36

radius=13

now ,replace.

`\begin{gathered} \text{Area}_(cir\sec )=\pi r^2\cdot((\Theta)/(360)) \\ \text{Area}_(cir\sec )=\pi(13)^2\cdot((36)/(360)) \\ \text{Area}_(cir\sec )=\pi\cdot169\cdot((36)/(360)) \\ \text{Area}_(cir\sec )=53.0929 \\ \text{rounded} \\ \text{Area}_(cir\sec )=53.09\text{ square units} \end{gathered}`

I hope this helps you