Question

Use the quadratic formula to solve 5x^2+2x-3

Answer 1

assuming it equals 0
for
ax^2+bx+c=0
x=
`(-b+/- √(b^2-4ac) )/(2a)`

given
5x^2+2x-3=0
a=5
b=2
c=-3

x=
`(-2+/- √(2^2-4(5)(-3)) )/(2(5))`
x=
`(-2+/- √(4+60) )/(10)`
x=
`(-2+/- √(64) )/(10)`
x=
`(-2+/- 8 )/(10)`
x=(-2+8)/10 or (-2-8)/10
x=6/10 or -10/10
x=3/5 or -1