Question

The roller skating rink has a track that is circular. The inside of the rink can't be used, but has a diameter of 24 feet. The track is 6 feet wide and goes around the outside of the rink. What is the approximate area of the track?

Answer 1

The track surrounds the rink, it goes around the outside of the rink.

Area of the rink = area of a circle

Area of the track = area of a circle too

`\text{Area of circle = }\pi\text{ }* r^2`

Diameter of rink = 24 , radius of rink = 24/2 = 12

Area of rink = pi x (24/2)^2 = pi x 12^2= 3.142 x 144 = 452.448 square feet

Diameter of rink + track = 24 + 6+6 = 36, radius = 36/2= 18

Area of rink + track = pi x (18)^2 = 3.142 x 324 = 1018.008 square feet

Finally, Area of just the track = Area of track + rink - area of rink = 1018.008 - 452.448 = 565.56 square feet

Answer = 565.56 square feet