104k views
3 votes
Write this function in vertex form, and Identify its vertex x^2-4x-17

1 Answer

1 vote
x^2-4x-17 is the same as 1x^2 + (-4)x + (-17)

It is in the form y = ax^2 + bx + c where

a = 1
b = -4
c = -17

To find the value of h, we use this formula
h = -b/(2a)
h = -(-4)/(2*(1))
h = 4/2
h = 2

Plug this back into the original function to find k
k = x^2-4x-17
k = (2)^2-4(2)-17
k = 4-8-17
k = -4-17
k = -21

So we know that a = 1, h = 2 and k = -21 making
y = a(x-h)^2 + k
turn into
y = 1(x-2)^2 - 21
which is now in vertex form. The vertex is (h,k) = (2,-21)
User Roberto Canogar
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories