Question

The diagram below shows the arrangement of seats in the first three rows of an auditorium.

Answer 1

Given

`\begin{gathered} a=6 \\ n=15 \\ d=4 \end{gathered}`

It is an arithmetic progression

Solution

`T_n=a_1+(n-1)d`

Substitute the given into the equation

`\begin{gathered} T_(15)=6+(15-1)4 \\ T_(15)=6+(14)4 \\ T_(15)=6+56 \\ T_(15)=62 \\ \end{gathered}`

The final answer

Option C

`62seats`