Question

Angle θ lies in the second quadrant, and sin θ = 3/5

Answer 1

the answer is this because it is -4/5 cost
-3/4 tan

Answer 2

sin θ
`=(3)/(5)`

It is given that , Angle θ lies in the second quadrant.

In the right triangle, Perpendicular =3 units, and Hypotenuse = 5 Units

As, sinθ is positive in second Quadrant also.That is , sin(π-θ )=sin θ

Also,
`sin((\pi)/(2)-\Theta)=cos\Theta`

`sin (\Theta) = 3/5\\\\  (\Theta) =sin^(-1) (3)/(5) {\text{or}} (\Theta) =\pi -sin^(-1) (3)/(5)\\\\cos((\pi)/(2)-\Theta)= (3)/(5)\\\\ (\pi)/(2)-\Theta=cos^(-1)[(3)/(5)]\\\\ \Theta= (\pi)/(2)-cos^(-1)[(3)/(5)]`

So,
`\pi-\Theta= (\pi)/(2)+cos^(-1)(3)/(5), {\text{or}}\pi -sin^(-1) (3)/(5)`

are values of theta which lies in second quadrant.