Question

A garage door opener has a power rating of 350 watts.

If the door is in operation for 30 seconds, how many joules of energy are used? (Hint: Remember that 1 watt = 1 joule/sec) 350 J 11.7 J 10,500 J 0.086 J

Answer 1

10,500 J

Step-by-step explanation:

Answer 2

We Know, Power = Energy/Time
Substitute the known value. which is P = 350 watt, & T = 30 sec
350 = E/30
E = 350 * 30
E = 1050 Joules.

So, your answer is 1050 Joules.
Hope this helps! Keep studying!