Question

What is the maximum mass of glucose (C6H12O6) that can be burned in 10 g of oxygen?

Answer 1

`C_6H_(12)O_6 + 6 \ O_2 \to 6 \ CO_2 + 6 \ H_2O`
1 mole of glucose : 6 moles of oxygen

First calculate the number of moles of oxygen in 10 g:

`M=32 \ (g)/(mol) \\ m=10 \ g \\ n=(10 \ g)/(32 \ (g)/(mol))=0.3125 \ mol`

1 mole of glucose reacts with 6 moles of oxygen
x moles of glucose reacts with 0.3125 moles of oxygen

`x=(1 \ mol \cdot 0.3125 \ mol)/(6 \ mol) = (3125)/(60000) \ mol= (5)/(96) \ mol`

Now calculate the mass of 5/96 moles of glucose.

`M=180 \ (g)/(mol) \\ n=(5)/(96) \ mol \\ m=180 \ (g)/(mol) \cdot (5)/(96) \ mol=(900)/(96) \ g=9.375 \ g`

The maximum mass of glucose that can be burned in 10 g of oxygen is 9.375 g.