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Solve logarithm Equation: log2 (12b - 21) - log2 (b^2 - 3)=2

User Masahiko
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1 Answer

7 votes
Hn, well you should use the rule to answer this..
log_a(n)-log_a(m)=log_a ((n)/(m) )
Sorry if this doesn't seem to help, but here is the explanation:

log_2 ((12b-21)/(b^2-3) )=2

(12b-21)/(b^2-3) =4

12b-21=4(b^4-3)

0=4b^2-12b-12+21

0=4b^2-12b+9

0=4b^2-6b-6b+9

0=2b(2b-3)-3(2b-3)

0=(2b-3)(2b-3)

b= (3)/(2)
Hn, so from this information we can determine that this solution does not work. And so forth your solution set shall indeed be: {x= 0}

I wish you good luck on your homework and hopefully I was somewhat beneficial to your needs.

Best regards~ Sans
User Aakash
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8.3k points