Question

Hi it’s RoseI’m having trouble on this problem from my prep guide, need help solving it

Answer 1

The Equation of a Circle

If a circle has its center at the point (h, k) and has a radius r, the equation of the circle is:

`(x-h)^2+(y-k)^2=r^2`

We are only given the endpoints of the diameter of the circle (3, -2) and (-5, 8). We need to find its center and radius.

These facts will help us to find both parameters:

* The diameter passes through the center of the circle.

* The center of the circle is the midpoint of the diameter.

* The radius of the circle is half the length of the diameter.

The midpoint of the diameter can be calculated as:

`\begin{gathered} x_m=(3-5)/(2) \\ x_m=(-2)/(2) \\ x_m=-1 \end{gathered}`
`\begin{gathered} y_m=(8-2)/(2) \\ y_m=(6)/(2) \\ y_m=3 \end{gathered}`

The coordinates of the midpoint are (-1, 3) and it happens to be the center of the circle, thus h = -1 and k = 3.

To find the radius, we need to calculate the distance from the center to any of the endpoints. Let's use the points (-1, 3) and (3, -2) and use the formula of the distance:

`\begin{gathered} r^2=(3+1)^2+(-2-3)^2 \\ r^2=16+25 \\ r^2=41 \end{gathered}`

We don't need to calculate the value of r. Its square is enough to substitute in the general form of the circle to get:

`\boxed{\mleft(x+1\mright)^2+\mleft(y-3\mright)^2=41}`