Solve using elimination method. 2x+3y=7 and 4x+2y =-6 A) one of (32,-19) or (6,-5) B) one of (0,1) or (2,0) C) one of (-3,1) or (2,1) D) one of (4,–1) or (-4,5)

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asked May 26, 2015 172k views

2 votes

Solve using elimination method.

2x+3y=7 and 4x+2y =-6
A) one of (32,-19) or (6,-5)
B) one of (0,1) or (2,0)
C) one of (-3,1) or (2,1)
D) one of (4,–1) or (-4,5)

Mathematics
high-school

Sin Tribu asked

by Sin Tribu

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1 Answer

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$2x+3y=7|\cdot(-2)\\ 4x+2y=-6\\\\ -4x-6y=-14\\ 4x+2y=-6\\ -------\\ -4y=-20\\ y=5\\\\ 2x+3\cdot5=7\\ 2x+15=7\\ 2x=-8\\ x=-4$

D

Tammye answered Jun 1, 2015

by Tammye

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