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A container holds a combination of nickels and quarters. There are 156 coins in all, and their total value is $21.60. The system of equations models this situation, where x is the number of nickels and y is the number of quarters.

x+y=156
0.05x+0.25y=21.6
How many nickels and quarters are in the container?
A.
118 nickels and 38 quarters

B.
106 nickels and 50 quarters

C.
87 nickels and 69 quarters

D.
72 nickels and 84 quarters

1 Answer

5 votes
x+y=156
0.05x+0.25y=21.6

-1/4*/ x+y=156
1/20x+1/4y=216/10

-1/4x-1/4y=156*-1/4=-39

1/20x+1/4y=216/10
+--------------------------
-4/20x=-17,4

x=87

x+y=156

87+y=156 y=69

this question answer is
87 nickels and 69 quarters

User Aiguo
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