Register
The density of liquid oxygen at its boiling point is 1.14 \rm{kg/L} , and its heat of vaporization is 213 \rm{kJ/kg} . How much energy in joules would be absorbed by 3.0 L of liquid oxygen as it vaporized?
34.7k views
4 votes
The density of liquid oxygen at its boiling point is 1.14 \rm{kg/L} , and its heat of vaporization is 213 \rm{kJ/kg} .

How much energy in joules would be absorbed by 3.0 L of liquid oxygen as it vaporized?

User Tim Tharratt
by
7.6k points

1 Answer

3 votes
m = rho x Vwhere rho is the density of liquid oxygen, V volumem= 1.14 kg/L x 3 L = 3.42 kg
Energy = m times heat of vaporization Energy = 3.42 kg x 213 kJ/kgEnergy = 724.46 kJ
User Beril
by
7.9k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.8m questions

10.4m answers

Other Questions

At sea level, water boils at 100 degrees celcius and methane  boiled at -161 degrees celcius. Which of these substances has a stronger force of attraction between its particles? Explain your answer
Physical properties of minerals graphic organizer
A snowball is launched horizontally from the top of a building at v = 16.9 m/s. If it lands d = 44 meters from the bottom, how high (in m) was the building?
What type of rock is the Haystack rock (igneous, Metamorphic, or Sedimentary)
what is a device that transforms thermal energy to mechanical energy
Link Copied!