Question

What are the x– and y–intercepts of the graph of y = 2x^2 – 8x – 10?

Answer 1

x-intercepts are found by setting y=0

`y=2x^2-8x-10\rightarrow0=2x^2-8x-10`
factor out a 2
`0=2(x^2-4x-5)\rightarrow0=x^2-4x-5`

`0=(x-5)(x+1)` roots should be x=-1,5
therefore, x-intercepts are (-1,0) and (5,0)

y-intercepts are found by setting x=0

`y=2x^2-8x-10\rightarrow y=2(0)^2-8(0)-10`

`\rightarrow y=0-0-10=-10`
therefore, y-intercept is (0,-10)